(a) draw the intemediate and product structures, including. The starting material is a 6 carbon ring with a methyl substituent on carbon 2 and double bonds between carbons 1 and 2. There are 2 steps to solve this one.
SOLVED Consider the reaction of 2methyl1,3cyclohexadiene with HCl
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Consider the reaction of 2‑methyl‑1,3‑cyclohexadiene with hcl.
Assuming that the reaction takes place at a very low temperature: Protonation of the double bond: (a) draw the intermediate and product. Here’s the best way to solve it.
The most stable intermediate will have the positive charge on the more substituted carbon (carbon 3). The reaction involves the following mechanism steps: Assuming that the reaction takes place at a very low temperature, draw the intermediate and product structures,. Assuming that the reaction takes place at a very low temperature:
Assuming that the reaction takes place at a very low temper iture, draw the intermediate and product structures, including any.
